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Delhi University MCA Previous Year Questions (PYQs)

Delhi University MCA Logical Ability And Logical Reasoning PYQ


Delhi University MCA PYQ 2019
X works twice as fast as Y . Y alone can finish the work in nine days . X and Y together can finish the work in _____ days.





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2019 PYQ

Solution


Delhi University MCA PYQ 2019
Average of ten numbers in a list is 25.If one of the numbers in the list is exchanged with another number the average of the new list increases by 5. What is the new number included in the list , if the original number was 15?





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2019 PYQ

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Delhi University MCA PYQ 2019
How much of acid is in the 10 liter of a 60% solution, of acid and water solution?





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2019 PYQ

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Delhi University MCA PYQ 2019
What is the next term in the series? 2, 7, 14, 23, 34, ______





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2019 PYQ

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Delhi University MCA PYQ 2019
The code of DOG is ITL , what is the code of ITL?





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2019 PYQ

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Delhi University MCA PYQ 2021





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2021 PYQ

Solution

A-------15
B-------10
C-------12

Total work (LCM of A,B,C) = 60
Work done by B and C in a day = (6+5)=11

B and C word done in 4 days = 44
Remaining work for A=16

A completes 4 work in a day, so A take 4 more days to complete 16 works.

Delhi University MCA PYQ 2020
Find the odd man out: 
1, 4, 27, 16, 125, 36, 216, 64, 729, 100





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2020 PYQ

Solution

The pattern of the series is 13, 22, 33, 42, 53, 62, 73. ..... 
Odd Term 216.

Delhi University MCA PYQ 2020
An athlete has to cover a distance of 6 Kms in 90 Minutes. He covers two-third of the distance in two-thirds of the total time. To cover the remaining distance in the remaining time, his speed should be____ Km/Hr. ?





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2020 PYQ

Solution

An athlete needs to cover 6 km in 90 minutes.
Given that he covers 2/3 of the distance in 2/3 of the total time
⇒ he covers 2/3 of 6 km in two-thirds of 90 minutes
⇒ He covers 4 km in 60 minutes.
Now he needs to cover the remaining 2 km in remaining 30 minutes
Distance = 2 km
Time =30 minutes =1/2 hour
Required Speed =2/(1/2)km/hr = 4km/hr

Delhi University MCA PYQ 2020
A and B can complete a work in 15 days. B and C can complete the same work in 20 days. If A, B and C together can finish it in 10 days, then A and C can complete the same work in____days.





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2020 PYQ

Solution

One Day work of A+B = 1/15
One Day work of B+C = 1/20
Lwt One Day work of A+C = 1/x
One Day work of A+B+C = 1/10 
2.One Day work of A+B+C =(One Day work of A+B)+(One Day work of B+C)+(One Day work of A+C)
210=115+110+1x
x=12
A+C can complete the same work in 12 days.

Delhi University MCA PYQ 2020
If 2x = (1024)1/5, what is the value of x ?





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2020 PYQ

Solution

2x=102415
2x=(210)1/5
2x=210/5
2x=22
x=2


Delhi University MCA PYQ 2020
Two trains each 500 metres long, are running in opposite directions on parallel tracks. If their speeds are 50 km/hr and 40 km/hr respectively, the time taken by the slower train to pass the driver of the faster one is _______seconds





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2020 PYQ

Solution

Relative speed = (50 + 40) km/hr
=(90×518)m/sec
=25 m/sec.
We have to find the time taken by the slower train to pass the Driver of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
∴ Required time (500×125​)=20sec.

Delhi University MCA PYQ 2020
The speed of a boat in still water is 12 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 30 minutes is





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Delhi University MCA Previous Year PYQDelhi University MCA DU MCA 2020 PYQ

Solution

Speed downstream = (12 + 3) kmph = 15 kmph.
Distance travelled = 15×3060km = 7.5km.


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